The following is a chart of production output for a given material input (that is, how many bullets or jackets you can make with a certain number of pounds of copper strip, lead wire, etc.). Naturally, there are variables in the design of bullets that require certain general assumptions, so that you may actually make a few more or less from the same material depending on the specific bullet. But in general this is a reliable planning guide for matching jacket and core material purchases, and calculating your production costs.
For a discussion of how to determine production speed, see Production Speed page. To find the current cost of copper, jackets, lead wire, and other supplies, see the Price List page.
Material  Jackets/50lb spool  Max.Wt./Jacket 
5/8in x .030T CU30625 50lb coil  8,205  18.97 gr. 
1in x .030T CU30100 50lb coil  5,128  50.43 gr. 
1.25in x .030T CU30125 50lb coil  4,102  79.78 gr. 
1.25in x .050T CU50125 50lb coil  2,461.5  132.97 gr. 
1.4in x .094T CU94140 50lb coil  1,169  315.23 gr. 
How to Calculate Jacket Quantity and Maximum Weight  
Assumptions: You will use Corbin's deepdrawing grade ASTM C11000 copper to draw the jackets. The density of the copper is 0.325lb/cuin. The copper is sold in "pancake" or flat coils of 50lb weight, in standard width/thickness dimensions as follows:

Width in.  Thickness in.  Crosssectional Area sqin.  Length in./50 lb Jackets per coil  Pounds  Max.Jacket Wt. Grains 
5/8  .030  0.01875  8,205  0.00271  18.97 
1  .030  0.03  5,128  0.0072049  50.43 
1.25  .030  0.0375  4,102.5  0.0113975  79.79 
1.25  .050  0.0625  2,461.5  0.0189959  132.97 
1.4  .094  0.1316  1,169  0.045034  315.23 
To calculate the scrap weight for recovery (sale of scrap copper), simply subtract the area of each disk from the area of the square (strip width squared) from which it is punched, and subtract the disk area from the square area. Multiply this remaining area by thickness, to obtain volume. Multiply the volume times the density of copper for the weight. You can then call a local scrap metal recovery firm, and ask what the current purchase rate may be for pure copper, by the pound. Multiply this dollar value by the scrap weight, subtract from your material cost, and you have the net price of the jackets.
 S = Scrap Weight, pounds
 W = strip width, in inches
 T = strip thickness, inches
 D = Density, lb/cuin (.325)
 Q = Quantity of jackets per 50 lbs
S = (W^2  ((W  .03)/2)^2 * Pi) * T * D * Q
To break this down in simple terms...
 Calculate area of the disk = width of strip minus .03, divided by 2, squared, times 3.14159 (Pi).
 Calculate the area of the square from which this disk is cut = width of strip squared.
 Subtract disk area from square area. The difference is the scrap area.
 Multiply the scrap area by the thickness of the strip. This is scrap volume.
 Multiply scrap volume by density of material (.325 lb/cuin). This is weight of scrap in pounds for one jacket.
 Multiply the weight of scrap for one jacket times number of jackets made with 50 lbs of material. This is your total scrap.
For any strip width, the number of jackets you can make in any weight of material is simply the length of that coil divided by the width. Normally, you don't know the length but you do know the weight, width, and thickness. Here is how to calculate the length and number of jackets you can make:
 The density of any material is the weight divided by the volume. You know the density = 0.325 lb/cuin and the weight = 50 lbs.
 Volume, therefore, is weight divided by density. Divide 50 lbs by 0.325 lbs/cuin. The answer is 153.84615 cubic inches.
 The volume is the width times thickness times length. We know volume, width and thickness. We can find length.
 Length = volume divided by the width times thickness (which is crosssectional area). L = 153.84615 / (w * t)
 For a 1.25in wide strip of .050 thickness, multiply .050 x 1.25 = 0.0625 square inches (cross sectional area).
 Now divide the volume (153.84615) by the cross sectional area (0.0625) and you have length of 2,461.5384 inches. For practical purposes, this can be considered 2,461 jackets from the 50lb coil.
 Divide the cost of the strip coil, less the recovery cost for the scrap, by the number of jackets. That is your material cost per jacket.
 J = Jackets per coil
 A = Cross sectional area (width times thickness)
J = 153.84615 / A
A = Width * Thickness
Lead Core Calcuations 
Calculating your cost per bullet for lead cores is straightforward. There are 7,000 grains in a pound. A 10lb spool of lead wire contains 70,000 grains. Your bullet weight is the combination of core weight and jacket weight (if a jacket is used). Therefore, simply subtract the estimated jacket weight from the bullet weight, and divide the remaining core weight into 70,000 to find out how many bullets you can make with one spool of wire. Jacket weight is not always known in advance, but you can estimate closely enough for reasonable calculations. A normal 224 jacket (which means, about 0.705in long, and works for all the 5.7, 5.65mm, .223, .220, .225, etc. calibers) weighs about 15 grains. A .243 or .257 jacket can push that to 2025 grains. A typical 30 caliber bullet will be around 3040 grains. Longer and heavier wall jackets in a given diameter weigh more than shorter, thinner jackets, of course. But a general estimate is usually close enough to be useful. Later you can actually weigh the jacket you plan to use, and recalculate based on whatever it may be. Bullets per spool of wire = 70,000 divided by core weight per bullet. A carton of four spools weighs 280,000 grains. If you are making 180 grain .308 bullets, and the jackets weigh about 40 grains, then each bullet uses 140 grains of lead. Divide 280,000 by 140 and you will find that you can make 2,000 bullets with a carton of lead wire. That means you should order 8 bags of .308 jackets (250 per bag) for each carton of lead wire. If you were making 55 grain 224 bullets, and the jackets weighed 12 grains (rimfire case jackets, perhaps), then the core weight per jacket would be 55  12 = 43 grains. Dividing 280,000 grains in a 4spool carton by 43 = 6,511 bullet cores. So you would want to make that number of jackets to match the core supply. You can see how easy it is to calculate how much lead wire you need to make any given weight and quantity of bullet. 
To determine material cost for a given bullet, calculate the core weight you plan to use. If you are making a 450 grain .458 rifle bullet, for instance, and the jacket you are making from copper tubing weighs about 70 grains, then the core weight will be 450  70 = 380 grains. Divide this 380 grains into 70,000 grains for a spool of wire. The answer is 184 (always ignore fractions when calculating the bullet quantity from weight). Now, divide the cost of a spool of wire by 184. This is the core cost per bullet. The jacket cost is either what you pay for a package divided by the quantity in the package, or it is the cost of the tubing or strip divided by the quantity of jackets you can make from that amount of material. With copper tubing, the number of jackets per foot of tubing is the length of the jacket plus half the caliber plus the saw cut width divided into 12. Most of the time, you can estimate that a jacket will be about an inch long, for typical bullet weights in the medium and larger bores (not huge bores like .510, of course, and not for extreme high BC, extra long or heavy bullets). So add half the caliber to 1, and add about .030 more for the saw cut. In a .458, this would mean each bullet uses 1.0 + 0.229 + .030 or 1.259 inches of tubing. To be on the safe side, round this up to 1.3 inches per bullet. Then if you purchase, say, 50 feet of tubing total, you know this is 50 x 12 or 600 inches, and divided by 1.3 per bullet makes 461 bullets. If you paid $150 for the tubing (only as a math example: this is NOT the actual price at any given time), then divide 150 by 461 and your jacket cost is 32.538 cents. Add to this your cost of lead, and you will know what the materials cost. 